5x^2+14x-115=0

Solution for 5x^2+14x-115=0 equation:

5x^2+14x-115=0

a = 5; b = 14; c = -115;
Δ = b2-4ac
Δ = 142-4·5·(-115)
Δ = 2496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2496}=\sqrt{64*39}=\sqrt{64}*\sqrt{39}=8\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-8\sqrt{39}}{2*5}=\frac{-14-8\sqrt{39}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+8\sqrt{39}}{2*5}=\frac{-14+8\sqrt{39}}{10}
$